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CoreMathematics · P5–P6

Model drawing: how to turn a word problem into bars

The Singapore bar model, step by step — when to use a part-whole model, when to use a comparison model, and the mistakes that cost marks.

Use this method when…

Model drawing is the method most Singapore students meet first and abandon soonest — usually right when it starts being useful. By P6 the problems have too many moving parts to hold in your head, and a bar model is what stops a hard question from becoming a guessing game.

The core idea is simple: a bar stands for a quantity, and equal units must be drawn equal. Everything else follows.

The two models

Almost every P5–P6 problem uses one of two shapes.

Part-whole — quantities combine into a total. Draw one long bar split into sections.

TotalPartPartWhole
Part-whole: the sections together make the total.

Comparison — quantities are measured against each other. Draw the bars stacked, aligned at the left edge, so the difference is visible as an overhang.

SmallerLargerdifference
Comparison: aligned at the left, so the gap between them is visible.

Choosing wrongly is the single most common reason a model “doesn’t work”. If the question says more than, fewer than, or times as many, it is a comparison model, even when a total is also given.

Worked example

Aisha and Ben share $120. Aisha gets $30 more than Ben. How much does Ben get?

“More than” tells you this is a comparison model. Ben is the smaller quantity, so make Ben 1 unit.

Ben1uAisha1u$30$120
Aisha's bar is Ben's bar plus $30. Both share the same 1-unit block.

Now read the total off the drawing:

1u + 1u + 30 = 120
        2u   = 120 − 30
        2u   = 90
        1u   = 45

Ben gets $45. Aisha gets 45 + 30 = $75.

Always check against both facts in the question: 45 + 75 = 120 ✓, and 75 − 45 = 30 ✓. A model that satisfies only one is a model you’ve misdrawn.

When quantities are transferred

Transfer problems (“A gives B 24 stickers”) are where models earn their keep. The trick is to draw two models — before and after — and look for what didn’t change.

Raj has 3 times as many stickers as Mei. Raj gives Mei 24 stickers, and now they have the same number. How many did Raj have at first?

Before the transfer:

Mei1uRaj1u1u1u
Raj has 3 times as many, so his bar is 3 equal units — the same size as Mei's.

After Raj gives Mei 24, the two bars are equal:

Mei1u+24Raj3u − 24
Both bars now the same length — that equality is the equation.

Reading straight off the second drawing: Mei has 1u + 24, Raj has 3u − 24, and they are equal.

3u − 24 = 1u + 24
     2u = 48
     1u = 24

Raj had 3 × 24 = 72 stickers.

Check: Raj 72, Mei 24. After the transfer, 48 and 48 ✓.

Notice what made this work: the total never changed (96 stickers throughout). Spotting the quantity that stays constant is the key to most transfer problems.

Common mistakes

Quick check

Draw a model for this, then solve it:

A rope is cut into two pieces. One piece is 4 times as long as the other. The longer piece is 96cm longer than the shorter. How long was the rope?

Answer

Comparison model: shorter = 1u, longer = 4u, so the difference is 3u.

3u = 96
1u = 32

Rope = 1u + 4u = 5u
     = 5 × 32

The rope was 160cm.

Check: shorter 32cm, longer 128cm. Difference 96 ✓, and 128 is 4 × 32 ✓

Now practise it

ExamKaki drills this method on real past-year school papers, and explains every answer as you go.

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